While I was trying to port m68k code (a software interrupt) I got the
response of a tester that the code in question was not executed,
although a noticeable slow down on the part of the OS could be
noticed. Before I grope in the dark and confront him with different
approaches, I decided first to exclude my private speculation.
I post here the relevant code snippet and the question.
Code:
static const struct EmulLibEntry irqgate =
{
TRAP_LIB, 0, (void (*)()) code_entry_morphos
};
INTERRUPT long code_entry_morphos( void)
{
struct mydata *md = (APTR) REG_A1;
#else
ASM SAVEDS INTERRUPT long code_entry(
REG(a1, struct mydata *md) )
{
#endif
struct timerequest *tr;
if ( (tr = (struct timerequest *)
RemHead( &md->irqport->mp_MsgList)) )
{
tr->tr_node.io_Command = TR_ADDREQUEST;
tr->tr_time.tv_micro = md->timeout;
BeginIO( &tr->tr_node);
...normal work is done here...
}
#if defined(__MORPHOS__)
REG_SR |= 4; /* Set virual Z flag */
#endif
return 0;
}
A part of the initialisation looks like this,
Code:
#if defined(__MORPHOS__)
md->timer_irq->is_Code = (void (*)()) &irqgate;
#else
md->timer_irq->is_Code = (void (*)()) code_entry;
#endif
md->irqport->mp_Flags = PA_SOFTINT;
Now my questions, what to put in mp_Sigtask?
Code:
a) md->irqport->mp_SigTask = (struct Task *) md->timer_irq;
as used for m68k, or
Code:
b) md->irqport->mp_SigTask = (struct Task *) &irqgate;
The interrupt is started as followed,
Code:
/* Start one time, rest managed by interrupt code */
md->request->tr_node.io_Command = TR_ADDREQUEST;
md->request->tr_time.tv_micro = md->timeout;
BeginIO( &md->request->tr_node);
Can someone enlighten me?
Thanks in advance.
